Geeks!

I actually think this is funny because I used to calculate these in college:

1st part:
[0.002+e^(2*Pi)] = 535.4936555

2nd part:
The Limit of the sum of (1/2^n) as n goes to infinity = 1

So the check is made out for $536.49

I recall that log functions, calculus, complex numbers, Bernoulli trials, and even representations were all part of my engineering life about 10 years ago. Today I can barely derive linear functions with out some study.